Java long compareTo(Long anotherLong) method example

public int compareTo(Long anotherLong)

The compareTo(Long anotherLong) method of Longclass returns the value 0 if this Long is equal to the argument Long; a value less than 0 if this Long is numerically less than the argument Long; and a value greater than 0 if this Long is numerically greater than the argument Long (signed comparison).

Requires Java 1.2 and up

Below is a simple java example on the usage of compareTo(Long anotherLong) method of Long class.

package com.javatutorialhq.java.examples;

import java.util.Scanner;

/*
 * This example source code demonstrates the use of  
 * compareTo(Long anotherLong) method of Long class
 */

public class LongCompareToExample {

	public static void main(String[] args) {
		
		// Ask for user input
		System.out.print("Enter the first value:");
		
		// declare a scanner object to read the user input
		Scanner s = new Scanner(System.in);
		
		// assign the input to a variable
		Long value1 = s.nextLong();
		
		
		// Ask for another value
		System.out.print("Enter the second value:");
		Long value2 = s.nextLong();
		
		// compare the two user input
		int result = value1.compareTo(value2);
		
		// interpret the result
		if(result == 0){
			System.out.println("They are equal");
		}else if(result > 0){
			System.out.println("First Value is greater than the second");			
		}else{
			System.out.println("First Value is less than the second");			
		}		
		
		// close the scanner object
		s.close();
	}

}

Below is the sample output when you run the above example.

• Java Long Class Tutorial
• Java Tutorial

• Oracle Java Documentation