Java Long highestOneBit(long i) method example

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Java Long highestOneBit(long i) method example 2018-02-16T07:26:13+00:00

java.lang.Long highestOneBit(long i)

Description

The Long.highestOneBit(long i) java method returns a long value with at most a single one-bit, in the position of the highest-order (“leftmost”) one-bit in the specified long value. Returns zero if the specified value has no one-bits in its two’s complement binary representation, that is, if it is equal to zero.

Make a note that the highestOneBit() method of Long class is static thus it should be accessed statically which means the we would be calling this method in this format:

Long.compare(method args)

Non static method is usually called by just declaring method_name(argument) however in this case since the method is static, it should be called by appending the class name as suffix. We will be encountering a compilation problem if we call the java highestOneBit method non statically.

Method Syntax

public static long highestOneBit(long i)

Method Argument

Data Type Parameter Description
long i the value whose highest one bit is to be computed

Method Returns

The highestOneBit(long i) method of Long class returns a long value with a single one-bit, in the position of the highest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Compatibility

Requires Java 1.5 and up

Java Long highestOneBit(long i) Example

Below is a simple java example on the usage of highestOneBit(long i) method of Long class.

Sample Output

Below is the sample output when you run the above example.

Java Long highestOneBit(long i) example output

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