Java Float isFinite() method example

public static boolean isFinite(float f)

The isFinite()  method of Float class returns true if the argument is a finite floating-point value, false otherwise.

Java 1.8

The method isFinite(float f) is simply a way to check if the method argument is a finite floating point. This is a very simple method of Float class however make note that this method is static. Thus it needs to be accessed statically which means that we should use this method in the format Float.isFinite(float f);

Below is a simple java example on the usage of isFinite(float f) method of Float class.

package com.javatutorialhq.java.examples;

import java.util.Scanner;

import static java.lang.System.*;

/*
 * This example source code demonstrates the use of 
 * isFinite(float f) method of Float class.
 */

public class FloatIsFiniteExample {

	public static void main(String[] args) {
		
		// Ask user input
		System.out.print("Enter Desired Value:");
		// declare the scanner object
		Scanner scan = new Scanner(System.in);
		// use scanner to get value from user console
		Float userInput = scan.nextFloat();
		// close the scanner object
		scan.close();		
		// check if the float input is finite floating point
		boolean check = Float.isFinite(userInput);
		out.println("is the value entered finite? " + check);
		
	}

}

Basically on the above example, we just ask for user input on the console and then we use the scanner object to get the float input. After that we assign the value to an Float wrapper class and we then we check if the user input is a finite floating point.

Below is the sample output when you run the above example.

• Java Float Class Tutorial
• Java Tutorial

• Oracle Java Documentation