java.lang.Character isISOControl(int codePoint)
Description
The isISOControl(int codePoint) method of Character class is static thus it should be accessed statically which means the we would be calling this method in this format:
Character.isISOControl(int codePoint)
Non static method is usually called by just declaring method_name(argument) however in this case since the method is static, it should be called by appending the class name as suffix. We will be encountering a compilation problem if we call the java isISOControl() method non statically.
Method Syntax
public static boolean isISOControl(int codePoint)
Method Argument
| Data Type | Parameter | Description |
|---|---|---|
| int | codepoint | the character (Unicode code point) to be tested. |
Method Returns
The isISOControl(int codePoint) method of Character class returns true if the character is an ISO control character; false otherwise.
Compatibility
Requires Java 1.5 and up
Java Character isISOControl(int codePoint) Example
Below is a simple java example on the usage of isISOControl(int codePoint) method of Character class.
package com.javatutorialhq.java.examples;
import java.util.Scanner;
/*
* This example source code demonstrates the use of
* isISOControl(char ch) method of Character class.
*/
public class CharacterIsISOControlCharExample {
public static void main(String[] args) {
// Ask for user input
System.out.print("Enter an input:");
// use scanner to get the user input
Scanner s = new Scanner(System.in);
// gets the user input
char[] value = s.nextLine().toCharArray();
// close the scanner object
s.close();
// check if user input is an ISO control character
for (char ch : value) {
boolean result = Character.isISOControl(ch);
// print the result
if(result){
System.out.println("character " + ch
+ " is an ISO control character? " + result);
}
else{
System.out.println("character " + ch
+ " is not an ISO control character? " + result);
}
}
}
}
Sample Output
Below is the sample output when you run the above example.
