java.lang.Character isLetterOrDigit(int codePoint)
Description
A character is considered to be a letter or digit if either isLetter(codePoint) or isDigit(codePoint) returns true for the character.
The isLetterOrDigit(int codePoint) method of Character class is static thus it should be accessed statically which means the we would be calling this method in this format:
Character.isLetterOrDigit(int codePoint)
Non static method is usually called by just declaring method_name(argument) however in this case since the method is static, it should be called by appending the class name as suffix. We will be encountering a compilation problem if we call the java isLetterOrDigit() method non statically.
Method Syntax
public static boolean isLetterOrDigit(int codePoint)
Method Argument
| Data Type | Parameter | Description |
|---|---|---|
| int | codepoint | the character (Unicode code point) to be tested. |
Method Returns
The isLetterOrDigit(int codePoint) method of Character class returns true if the character is a letter or digit; false otherwise.
Compatibility
Requires Java 1.5 and up
Java Character isLetterOrDigit(int codePoint) Example
Below is a simple java example on the usage of isLetterOrDigit(int codePoint) method of Character class.
package com.javatutorialhq.java.examples;
/*
* This example source code demonstrates the use of
* isLetterOrDigit(int codePoint) method of Character class.
*/
public class CharacterIsLetterOrDigitCodepointExample {
public static void main(String[] args) {
// initialize a codepoint
int codepoint = 89;
// check if the codepoint is a letter/digit or not
boolean checkBool = Character.isLetterOrDigit(codepoint);
// print result
if(checkBool){
System.out.print("Codepoint '"+codepoint+"' is a letter/digit");
}
else{
System.out.print("Codepoint '"+codepoint+"' is not a letter/digit");
}
}
}
Sample Output
Below is the sample output when you run the above example.
