Java StringTokenizer hasMoreElements() method example

public boolean hasMoreTokens()

Specified by:

hasMoreElements in interface Enumeration

The hasMoreElements() method returns true if there are more tokens; false otherwise.

Requires Java 1.0 and up

Below is a java code demonstrates the use of hasMoreElements() method of StringTokenizer class. The example presented might be simple however it shows the behaviour of the hasMoreElements() method.

package com.javatutorialhq.java.examples;

import java.util.StringTokenizer;

/*
 * This example source code demonstrates the use of  
 * hasMoreElements() method of StringTokenizer class.
 * 
 */

public class StringTokenizerHasMoreElementsExample {

	public static void main(String[] args) {
		
		//declare a new String with tokens delimited by $
		String input = "William$Ryan$Grace$Travis$Vince";
		
		/*
		 * initialize our StringTokenizer using input 
		 * as source String and $ as the delimiter
		 */

		StringTokenizer tokenizer = new StringTokenizer(input,"$");
		
		// print all tokens
		while(tokenizer.hasMoreElements()){
			System.out.println(tokenizer.nextElement());
		}	
		
	}

}

The above java example source code demonstrates the use of hasMoreElements() method of StringTokenizer class. Basically we just declared a new String object with tokens delimited by “$”. This made it possible by making use of one of the constructor of StringTokenizer class that accepts the String input and delimiter. Since the hasMoreElements() check if there are still available tokens on the buffer, we can use this as a check on our while loop. The while loop will iterate until there are tokens available. And we used the nextElement() to get the current token and advance to the next one. The combination of this two are the fundamentals in using the StringTokenizer.

Below is the sample output when you run the above example.

• Java StringTokenizer Class Tutorial
• Java Tutorial

• Oracle Java Documentation